Laboratornaia Rabota 3 Po Fizike 8 Klass -

with a standard table of specific heat capacities to identify the metal (e.g., iron, brass, or aluminum). Note that small deviations are normal due to heat loss to the calorimeter walls and the air during transfer ( 1.4.2 ).

The heat balance equation states that the heat gained by the water ( Qgaincap Q sub g a i n end-sub ) equals the heat lost by the metal body ( Qlostcap Q sub l o s t end-sub laboratornaia rabota 3 po fizike 8 klass

To determine the specific heat capacity of a solid body (typically a metal cylinder) by comparing the heat given off by the body to the heat received by water in a calorimeter. with a standard table of specific heat capacities

): Heat the metal body in boiling water. Its temperature will be approximately ): Heat the metal body in boiling water

Qgain=cw⋅mw⋅(θ−t1)cap Q sub g a i n end-sub equals c sub w center dot m sub w center dot open paren theta minus t sub 1 close paren

Quickly transfer the heated metal body from the boiling water into the calorimeter with cold water. Stir the water gently with the thermometer or a stirrer. Final temperature (

Qlost=cb⋅mb⋅(t2−θ)cap Q sub l o s t end-sub equals c sub b center dot m sub b center dot open paren t sub 2 minus theta close paren (specific heat of water). is the unknown specific heat of the metal.